Give a child a robot, he'll play for an hour. Teach him to build, and he'll play forever.
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I think there is an error here, pretty sure it should be:mightor wrote:Here are some #defines for min and max for 3 numbers:Code: Select all
#define min3(a, b, c) (a < b) ? ((a < b) ? a : c) : ((b < c) ? b : c)
Code: Select all
#define min3(a, b, c) (a < b) ? ((a < c) ? a : c) : ((b < c) ? b : c)Actually, since they are macros the nested min version (which I would recommend using instead of a min3 or min7 or custom min function for some other number of parameters) expands to exactly the same code as the custom min macro.muntoo wrote: For reference, the exact equivalents are:Although they're less optimized.Code: Select all
#define min(a,b) (a<b?a:b) #define max(a,b) (a>b?a:b) #define min3(a,b,c) min(a,min(b,c)) #define max3(a,b,c) max(a,max(b,c))
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int foo = (a > b) ? a : b;
1 ---------^^^^^
2 ------------------^
3-----------------------^ Code: Select all
if (a > b)
foo = a;
else
foo = b;sry but what means "nested min (max) versions"? Already built-in? where? how? or how exactly to use min3...min7 or what exactly instead of this?Actually, since they are macros the nested min version (which I would recommend using instead of a min3 or min7 or custom min function for some other number of parameters) expands to exactly the same code as the custom min macro.
What he means is,doc-helmut wrote:sry but what means "nested min (max) versions"? Already built-in? where? how? or how exactly to use min3...min7 or what exactly instead of this?
min3(a,b,c) will compile to the same code as min(a,min(b,c)), pertaining to the code in this post.Code: Select all
min3(a,b,c)
min(a,min(b,c))
min(a,(b<c?b:c))
(a<(b<c?b:c)?a:(b<c?b:c))
Optimized: t=b<c?b:c; a<t?a:tmin3(a,b,c) is this:
Code: Select all
(a<b?(a<c?a:c):(b<c?b:c))